It's not every day that one of my open problems is solved, especially one that I asked about over three decades ago. Matt Kovacs-Deak, Daochen Wang and Rain Zimin Yang just posted a paper showing that if you have a Boolean function \(f\) and two polynomials \(p\) and \(q\) of degree at most \(d\) such that \(f(x)=p(x)/q(x)\) for every \(x\) of length \(n\) then \(f\) has decision tree complexity at most \(2d^4\).
Noam Nisan and Mario Szegedy had this beautiful paper in the early 90s showing that if a low-degree polynomial approximated a Boolean function, the decision tree complexity, the number of bits you needed to query from the input to decide the output, was bounded by the degree. For rational functions, that wasn't true, the majority function can be approximated by the ratio of two low-degree polynomials. This was the main tool used by Beigel, Reingold and Spielman when they showed that the complexity class PP is closed under intersection.
Motivated by the complexity class C\(_=\)P\(\cap\)co-C\(_=\)P, I asked Mario if a low-degree rational function exactly computed a Boolean function, then would that function have low decision tree complexity. Mario thought about it, said it was an interesting problem, and added it as an open question to the journal version of his paper with Nisan.
I gave the problem to every student who asked me for an open combinatorial problem, as well as every reasoning AI model I could get my hands on. Iyer et al. posted a paper that examined this problem and showed it true for symmetric functions but the general case remained open until now.
The main insight of Kovacs-Deak, Wang and Yang is to consider the minimum block sensitivity, which is usually an uninteresting property of a function. The majority function for example has large maximum and average block sensitivity but low min block sensitivity. Nevertheless, their proof bounded the min block sensitivity by twice the degree of the rational function and used it to get a degree reduction of the rational function by querying a small number of bits of the input. Nice.
I always joked that if I told people the complexity application of the problem they would lose interest. The question came out of work with Steve Fenner, Stuart Kurtz and Lide Li on An Oracle Builder's Toolkit. C\(_=\)P is a generalization of co-NP where we ask if a gap-P function (the difference of two #P functions) is zero. So C\(_=\)P\(\cap\)co-C\(_=\)P is a generalization of NP\(\cap\)co-NP. This new theorem implies the technical result that if P = PSPACE unrelativized then P = C\(_=\)P\(\cap\)co-C\(_=\)P relative to a generic oracle. This implies an oracle where P = C\(_=\)P\(\cap\)co-C\(_=\)P and the PH is infinite and another where C\(_=\)P\(\cap\)co-C\(_=\)P has no complete sets.
If you are more of a quantum person, C\(_=\)P\(\cap\)co-C\(_=\)P = PostEQP while PostBQP = PP, and this work shows quite a difference between these classes. PP has complete sets and if P = PP then the polynomial-time hierarchy and even the counting hierarchy collapses to P.
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