On Friday I will be flying back to the East Coast. Here is a puzzle to keep blog readers occupied while I am traveling.
I write two different numbers, one on each hand. You choose one of my hands at random, I show you the number on that hand. You now guess whether the number you've seen is larger than the number you haven't seen. Find a strategy for guessing such that, no matter what two numbers I write, you have greater than a 50% chance of being correct. (Borrowed from there.)
What if I have three hands and at any time you can choose to either keep the number I show you or discard it and move on to choosing another hand?
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